December 10, 2019

 E = Voltage /  I = Amps/ PF = Power Factor /  EFF = Efficiency /  HP = Horsepower To Find Direct Current Alternating Current Single Phase Two-Phase* Four-Wire Three Phase Amperes when Horsepower is known HP x 746 —— E x EFF HP x 746 ——- E x EFF x PF x 2 HP x 746 —— 2 x E x EFF x PF HP x 746 —— E x EFF x PF x 1.73 Amperes when Kilowatts are known KW x 1000 —— E KW x 1000 —— E x PF KW x 1000 —— 2 x E x PF KW x 1000 —— E x PF x 1.73 Amperes when “KVA” is known KVA x 1000 —— E KVA x 1000 —— 2 x E KVA x 1000 —— E x 1.73 Kilowatts E x I —— 1000 E x I x PF —— 1000 I x E x 2 x PF —— 1000 E x I x 1.73 x PF —— 1000 Kilovolt-Amperes “KVA”- I x E —— 1000 I x E x 2 —— 1000 E x I x 1.73 —— 1000 -Horsepower (Output) E x I x EFF —— 746 E x I x EFF x PF —— 746 I x E x 2 x EFF x PF —— 746 E x I x EFF x PF x 1.73 —— 746

Note: Direct current formulas do not use (PF, 2, or 1.73)
Single phase formulas do not use (2 or 1.73)
Two phase-four wire formulas do not use (1.73)
Three phase formulas do not use (2)
* For three-wire, two phase circuits the current in the common conductor is 1.41 times that in either of the other two conductors.